Given a string s of size n, we define the i-th rotation of s (for 0 ≤ i < n) as
si si+1 … sn−1 s0 … si−2 si−1 . |
Given two strings s and t, compute how many i-th rotations of s are equal to t.
For instance, for s = “abbabb” and t = “babbab” the answer is 2, corresponding to i = 2 and i = 5.
Input
Input consists of several cases, each one with two strings s and t with only lowercase letters. Assume 1 ≤ | s | = | t | ≤ 105. Every letter appears the same number of times in s and in t.
Output
For every case, print the number of i-th rotations of s that are equal to t.
Input
abbabb babbab abc acb abba bbaa zzzzz zzzzz
Output
2 0 1 5