Write a function digit_after_let(s) that given a string s returns a boolean and a character. The boolean is True when s has some digit after some letter, otherwise is False. The character has to be the first digit in s that comes out after some letter in the first case and the symbol ’$’ in the second one. You can use the string method isalpha() to check whether given a string it has at least one character and all its characters are letters. For instance, my_string.isalpha() is True when my_string is ’HeLLo’ or ’X’ and is False when my_string is ’He7TO’ or ’?;x’ or ’123456’.
>>> digit_after_let('123 456') (False, '$') >>> digit_after_let('Wrong Answer: -10- has to be -25-') (True, '1') >>> digit_after_let('451sTa') (False, '$') >>> digit_after_let('X@#2$Z5Y') (True, '2')